If cookies are sold for $1 each and oranges for $0.75 each, how many cookies and oranges were sold for a total of $8.25?

If cookies are sold for $1 each and oranges for $0.75 each, how many cookies and oranges were sold for a total of $8.25?

• A. 4 oranges and 5 cookies
• B. 3 oranges and 6 cookies
• C. 6 oranges and 3 cookies
• D. 5 oranges and 4 cookies

Answer: (B)

To solve the problem, we need to find the combination of cookies and oranges that totals $8.25. Cookies are sold for $1 each and oranges for $0.75 each. If we consider the combination of 3 oranges and 6 cookies, the calculation would be as follows: - The cost of 3 oranges: 3 oranges × $0.75/orange = $2.25 - The cost of 6 cookies: 6 cookies × $1/cookie = $6.00 When we add these two amounts together: $2.25 (oranges) + $6.00 (cookies) = $8.25 This confirms that selling 3 oranges and 6 cookies results in the correct total of $8.25. The other combinations do not yield this total when calculated, making option B the correct choice.

To solve the problem, we need to find the combination of cookies and oranges that totals $8.25. Cookies are sold for $1 each and oranges for $0.75 each.

If we consider the combination of 3 oranges and 6 cookies, the calculation would be as follows:

• The cost of 3 oranges: 3 oranges × $0.75/orange = $2.25

• The cost of 6 cookies: 6 cookies × $1/cookie = $6.00

When we add these two amounts together:

$2.25 (oranges) + $6.00 (cookies) = $8.25

This confirms that selling 3 oranges and 6 cookies results in the correct total of $8.25.

The other combinations do not yield this total when calculated, making option B the correct choice.